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		<title>expdp导出xml列报ORA-22924故障处理</title>
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<p>标题：<a href="https://www.xifenfei.com/2026/02/expdp-xml-ora-22924.html" target="_blank">expdp导出xml列报ORA-22924故障处理</a></p>
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<p>expdp导出xml列类型表报错</p>
<pre class="brush: bash; title: ; notranslate">
连接到: Oracle Database 11g Enterprise Edition Release 11.2.0.4.0 - 64bit Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options
启动 &quot;SYS&quot;.&quot;EXPDP_TBA1&quot;:  &quot;/******** AS SYSDBA&quot; tables=XFF.XML_TAB dumpfile=XML_TAB.dmp
    DIRECTORY=expdp_dir logfile=expdp_XML_TAB.log EXCLUDE=STATISTICS job_name=expdp_tba1
正在使用 BLOCKS 方法进行估计...
处理对象类型 TABLE_EXPORT/TABLE/TABLE_DATA
使用 BLOCKS 方法的总估计: 13.12 GB
处理对象类型 TABLE_EXPORT/TABLE/TABLE
处理对象类型 TABLE_EXPORT/TABLE/INDEX/INDEX
处理对象类型 TABLE_EXPORT/TABLE/CONSTRAINT/CONSTRAINT
处理对象类型 TABLE_EXPORT/TABLE/CONSTRAINT/REF_CONSTRAINT
ORA-31693: 表数据对象 &quot;XFF&quot;.&quot;XML_TAB&quot; 无法加载/卸载并且被跳过, 错误如下:
ORA-29913: 执行 ODCIEXTTABLEPOPULATE 调出时出错
ORA-22924: 快照太旧
已成功加载/卸载了主表 &quot;SYS&quot;.&quot;EXPDP_TBA1&quot;
******************************************************************************
SYS.EXPDP_TBA1 的转储文件集为:
  D:\XML_TAB.DMP
作业 &quot;SYS&quot;.&quot;EXPDP_TBA1&quot; 已经完成, 但是有 1 个错误 (于 星期六 2月 14 09:01:26 2026 elapsed 0 00:04:15 完成)
</pre>
<p>一般对于这些问题的解决思路是找出来异常的行的rowid,然后导出跳过异常行或者把对应的xml列置空,关键就是如何找出来该记录,这里自己写了一个plsql来找出来异常rowid</p>
<pre class="brush: sql; title: ; notranslate">
SQL&gt; declare
  2  page number;
  3  len number;
  4  c varchar2(10);
  5  charpp number := 8132/2;
  6  n number;
  7  v_sqlerrm varchar2(100);
  8  begin
  9  n := 0;
 10  for r in (select rowid rid from XFF.XML_TAB order by rowid) loop
 11  begin
 12  select dbms_lob.getlength (xmltype.getclobval(XML_COL)) into c from XFF.XML_TAB     where rowid = r.rid;
 13  v_sqlerrm := SQLERRM;
 14  insert into result values (n, r.rid, 'good', page, v_sqlerrm);
 15  commit;
 16  exception
 17  when others then
 18  dbms_output.put_line ('Error on rowid ' ||r.rid||' page '||page);
 19  dbms_output.put_line (sqlerrm);
 20  v_sqlerrm := SQLERRM;
 21  insert into result values (n, r.rid, 'bad',page,v_sqlerrm);
 22  commit;
 23  end;
 24  end loop;
 25  end;
 26  /
Error on rowid AAASO1AAKAAAH5bAAC page
ORA-22924: 快照太旧
ORA-06512: 在 &quot;SYS.XMLTYPE&quot;, line 138
Error on rowid AAASO1AAKAAAIPtAAZ page
ORA-22924: 快照太旧
ORA-06512: 在 &quot;SYS.XMLTYPE&quot;, line 138
Error on rowid AAASO1AAKAAAIRfAAU page
ORA-22924: 快照太旧
ORA-06512: 在 &quot;SYS.XMLTYPE&quot;, line 138
Error on rowid AAASO1AAKAAAIS9AAW page
ORA-22924: 快照太旧
ORA-06512: 在 &quot;SYS.XMLTYPE&quot;, line 138
Error on rowid AAASO1AAKAAAIT7AAW page
ORA-22924: 快照太旧
ORA-06512: 在 &quot;SYS.XMLTYPE&quot;, line 138
Error on rowid AAASO1AAKAAAIT/AAG page
ORA-22924: 快照太旧
ORA-06512: 在 &quot;SYS.XMLTYPE&quot;, line 138

PL/SQL 过程已成功完成。
</pre>
<p>然后expdp导出数据跳过这些异常的rowid的par文件</p>
<pre class="brush: bash; title: ; notranslate">
directory=expdp_dir
dumpfile=expdp_XFF.XML_TAB.dmp
logfile=expdp_XFF.XML_TAB.log
tables=XFF.XML_TAB
query=&quot;XFF.XML_TAB:WHERE rowid not IN  ('AAASO1AAKAAAH5bAAC','AAASO1AAKAAAIPtAAZ','AAASO1AAKAAAIT7AAW',
'AAASO1AAKAAAIT/AAG', 'AAASO1AAKAAAIRfAAU','AAASO1AAKAAAIS9AAW')&quot;
job_name=exp_1
</pre>
<p>数据可以正常到导出<br />
<a href="https://www.xifenfei.com/wp-content/uploads/2026/02/expdp.png"><img src="https://www.xifenfei.com/wp-content/uploads/2026/02/expdp.png" alt="expdp" width="1131" height="321" class="alignleft size-full wp-image-11989" /></a><br />
<hr />
也可以通过update语句直接把异常的xml值直接置空</p>
<pre class="brush: sql; title: ; notranslate">
update XFF.XML_TAB
set XML_COL = XMLType.createXML('')
where rowid in (select checked_rowid from result where status='bad');
</pre>
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